Answer:
a = 14 and d = 6.67
Explanation:
The nth term of an AP is given by :
![a_n=a+(n-1)d](https://img.qammunity.org/2022/formulas/mathematics/high-school/z3ggkqmhdr30c6f6y2dgecyqzzjyb67v0v.png)
Where
a is the first term and d is the common difference
ATQ,
An arithmetic sequence has the 7th term of 54 and the 13th term of 94 i.e.
![a+6d=54\ ......(1)\\\\a+12d=94\ ........(2)](https://img.qammunity.org/2022/formulas/mathematics/college/7sld2lufu2wfd5rg08lbaof6jin2o6xnsj.png)
Subtract equation (2) from (1).
a+6d-(a+12d) = 54-94
a+6d-a-12d = -40
-6d = -40
d = 6.67
Put the value of d in equation (1).
![a+6(6.666)=54\\\\a=54-39.96\\\\a=14.04](https://img.qammunity.org/2022/formulas/mathematics/college/upzntbc5mtbefo2j5abwg3j725h8f3m9v8.png)
or
a = 14
Hence, the first term is 14 and the common difference is 6.67.