Answer:
i. 1.63 s
ii. The negative time cannot be used in this context
Explanation:
i. Since h = −640t² and the rocket descends 1,690 m, h = -1,690 m (since there is a drop in height).
So, h = -640t²
t² = h/-640
t = √(- h/640)
Substituting h into the equation, we have
t = √(- h/640)
t = √[-(-1,690)/640]
t = √2.640625
t = 1.625
t ≈ 1.63 s
ii. So, the negative time cannot be used in this context because, the height drop is negative.