Question

Prob(Total time in process > t) = EXP(-t/T) T = (1/(Rp - Ri)) = (1 / Rs) R = min(Ri, Rp) u=R/Rp Dominic runs an appliance repair shop and sells replacement parts for appliances to walk in customers. Customer take an average of 5 minutes. It is a single phase system with 1 server. The coefficient of arrivals and the coefficient of processing times is 1.0. If Dominic's utilization were 80%, how many would be standing in line waiting to be served?

Answer 1

3.20 customers

Step-by-step explanation:

If one customer takes 5 minutes then in 1 hour =

60/5 = 12 minutes

This is the service rate

Utilization = arrival rate divided by service rate

0.80 = AR / 12

AR = 0.89x12

Arrival rate = 9.6/hour

We get average of those waiting in system

AR/SR-AR

= 9.6/(12-9.6)

9.6/2.4

= 4

4 x 0.80 = 3.2 this is the average of those waiting in line