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Identify the 31st term of an arithmetic sequence where a1 = 26 and a22 = −226.

−334
−274
−284
−346

User Anconia
by
4.1k points

2 Answers

4 votes

a1 = 26 and a22 = −226.

Answer:

A) −334

User Kannan K
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3.8k points
4 votes

Answer:

a31 = -334

Explanation:

Given:

a1 = 26

a22 = -226

Find:

a31

Computation:

a22 = a + 21d

-226 = 26 + 21d

d = -12

a31 = a + 30d

a31 = 26 + 30(-12)

a31 = 26 - 360

a31 = -334

User Slabgorb
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4.1k points