110k views
5 votes
In the cube shown below, the distance between vertices 2 and 6 is 15 cm.

If the cube is divided into two equal parts by a plane parallel to the face defined by vertices 2, 3, 6, and 7, what will be the area of the cross-section?
A.
45 sq cm
B.
15 sq cm
C.
225 sq cm
D.
60 sq cm
FALSE ANSWERS/SCAMS/TROLLS WILL IMMIDIATELY BE REPORTED!

User Rasheem
by
7.9k points

2 Answers

5 votes
256. sq cm Lol there
User Dcernahoschi
by
7.5k points
5 votes

Answer:

256 sq cm

Explanation:

cube is a three-dimensional figure with six congruent square faces. Since each face is congruent, each of the edges have the same length.

The cross-section described is shown below.

The cross-section is also a square which is congruent to the other faces of the cubes. Therefore, the edges of the cross-section will each measure 16 cm. Find the area by using the formula for the area.

A=lw

=(16cm) (16cm)

=256 sq cm

So, the area of the cross-section is 256 sq cm.

hope this helps some way

Explanation:

User Floris Kleijne
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories