Question

In the cube shown below, the distance between vertices 2 and 6 is 15 cm.

If the cube is divided into two equal parts by a plane parallel to the face defined by vertices 2, 3, 6, and 7, what will be the area of the cross-section?
A.
45 sq cm
B.
15 sq cm
C.
225 sq cm
D.
60 sq cm

Answer 1

The answer would be 256sq cm..

Answer 2

256 sq cm

Explanation:

cube is a three-dimensional figure with six congruent square faces. Since each face is congruent, each of the edges have the same length.

The cross-section described is shown below.

The cross-section is also a square which is congruent to the other faces of the cubes. Therefore, the edges of the cross-section will each measure 16 cm. Find the area by using the formula for the area.

A=lw

=(16cm) (16cm)

=256 sq cm

So, the area of the cross-section is 256 sq cm.

hope this helps some wayExplanation: