Complete question:
On the package for a certain brand of spinach seeds there is a guarantee that, if the printed instructions are followed, 63% of planted seeds will germinate. A random sample of 9 seeds is chosen. If these seeds are planted according to the instructions, find the probability that 4 of them germinate.
Answer:
![P(x = 4) = 0.1376](https://img.qammunity.org/2022/formulas/mathematics/college/oazdxpo7s1zomlnb60b6y5h0rn429fulhr.png)
Explanation:
Given
![n = 9](https://img.qammunity.org/2022/formulas/physics/college/szapvlbdmo01jmnqadac1b0zsp96pyidxa.png)
--- proportion that germinates
![p = 0.63](https://img.qammunity.org/2022/formulas/mathematics/college/xwe0ie0cmw1v4skz4l5c4ae1znooa1xp0k.png)
Required
P(x = 4)
This question follows a binomial distribution:
![P(x) = ^nC_x*p^x*(1-p)^{n-x](https://img.qammunity.org/2022/formulas/mathematics/college/js00h4001b6ksvfzu8yu3zs2coubroir1x.png)
When x = 4;
![P(x = 4) = ^9C_4*0.63^4*(1-0.63)^{9-4](https://img.qammunity.org/2022/formulas/mathematics/college/3yg4wg982g4kkgikltj058w8ygenybuanv.png)
![P(x = 4) = ^9C_4*0.63^4*(0.37)^5](https://img.qammunity.org/2022/formulas/mathematics/college/a8i16ds194m5gevskzmow9mwyp657rhaue.png)
![P(x = 4) = 126*0.63^4*0.37^5](https://img.qammunity.org/2022/formulas/mathematics/college/uyvjw207z345j5rglifqbbxop17p45xsdu.png)
![P(x = 4) = 0.13763895392](https://img.qammunity.org/2022/formulas/mathematics/college/1cbnk67exhdxj4307hzr6wmv5tz54l7rv0.png)