Answer:
![Area = 152cm^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/qs8k57xsab7t385l3duj0dt55qda5dz22b.png)
Explanation:
Given
See attachment for the prism net
Required
Calculate the area
First, calculate the area of the two congruent triangle:
![A_1 =2 * (1)/(2) * base * height](https://img.qammunity.org/2022/formulas/mathematics/high-school/ora5arsa23blhoz4cxubiw9uowwbcl5f2t.png)
Where
base = 6cm\ height = 4cm
So:
![A_1 =2 * (1)/(2) * 6cm * 4cm](https://img.qammunity.org/2022/formulas/mathematics/high-school/oprs6xh3lnwz9wp6g9iujyj8ak04c7bj9l.png)
![A_1 =24cm^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/kdktzeshk7do2ifjhs6601gm7evrc0ade9.png)
Calculate the area of the middle rectangle
![A_2 = Length * Width](https://img.qammunity.org/2022/formulas/mathematics/high-school/gcxp63sooxnq4rxl4dbjnssa94pm4t66mi.png)
![A_2 = 6cm * 8cm](https://img.qammunity.org/2022/formulas/mathematics/high-school/zm5on1c9zfz3ffjcitj0vokr9hq824jfet.png)
![A_2 = 48cm^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/i7cxbfg7ai469pmlauf79087uufv64pyfn.png)
Lastly, the area of the two congruent rectangles on both sides of the middle rectangle
![A_3 = 2 * Length *Width](https://img.qammunity.org/2022/formulas/mathematics/high-school/xbfgqgbo2y4wukk9hl5q4a2i3iw6br55hp.png)
![A_3 = 2 * 8cm * 5cm](https://img.qammunity.org/2022/formulas/mathematics/high-school/bug5fd91x7hmyxdki18nn8v5zyzw22xffb.png)
![A_3 = 80cm^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/3leb5rtj1s7tall7ipkt91xii4n80k3qpr.png)
So, the surface area of the net is:
![Area = A_1 + A_2 + A_3](https://img.qammunity.org/2022/formulas/mathematics/high-school/z6fwumopluroyo18omwni1n22choo0zj36.png)
![Area = 24cm^2 + 48cm^2 + 80cm^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/viuayb0htccvd4twf964opdh10aetg81tq.png)
![Area = 152cm^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/qs8k57xsab7t385l3duj0dt55qda5dz22b.png)