229k views
6 votes
Write an equation and solve.

A jar contained 10 marbles. The jar had five less than half as many as were on the table. How many marbles were on the table?

2 Answers

11 votes

Solution:

Let z represent the number of marbles on the table.

Note that:

  • J = 10
  • J = z/2 - 5

Thus, we can say that:

  • J = 10 = z/2 - 5

Adding 5 to both sides:

  • 5 + 10 = z/2 - 5 + 5
  • => 10 + 5 = z/2

Simplifying the LHS:

  • => 15 = z/2

Cross multiplication:

  • => 15 x 2 = z
  • => 30 = z

We can conclude that:

There were 30 marbles on the table.

User SalutonMondo
by
6.6k points
14 votes

Answer:

30 marbles

Explanation:

Let,

No. of marbles on the table be = x

So,

No. of marbles in the jar =
(x)/(2) - 5

We know that,

No. of marbles in the jar were 10

Therefore,

By the problem,

=>
(x)/(2) - 5 = 10

  • [On adding 5 on both sides]

=>
(x)/(2) - 5 + 5 = 10 + 5

  • [On simplification]

=>
(x)/(2) = 15

  • [On multiplying both sides with 2]

=>
(x)/(2) × 2 = 15 × 2

  • [On simplification]

=> x = 30

Hence,

Required no. of marbles on the table were 30. (Ans)

User Stewbob
by
6.5k points
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