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If 30,000 cm2 of material is available to make a box with a square base and an open top, what is the largest possible volume (in cm3) of the box?

User Ritaban
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1 Answer

5 votes

Answer:

The largest possible volume of the box is 2000000 cubic meters.

Explanation:

The volume (
V), in cubic centimeters, and surface area (
A_(s)), in square centimeters, of the box with a square base are described below:


A_(s) = l^(2)+h\cdot l (1)


V = l^(2)\cdot h (2)

Where:


l - Side length of the base, in centimeters.


h - Height of the box, in centimeters.

By (2), we clear
h within the formula:


h = (V)/(l^(2))

And we apply in (1) and simplify the resulting expression:


A_(s) = l^(2)+ (V)/(l)


A_(s)\cdot l = l^(3)+V


V = A_(s)\cdot l -l^(3) (3)

Then, we find the first and second derivatives of this expression:


V' = A_(s)-3\cdot l^(2) (4)


V'' = -6\cdot l (5)

If
V' = 0 and
A_(s) = 30000\,cm^(2), then we find the critical value of the side length of the base is:


30000-3\cdot l^(2) = 0


3\cdot l^(2) = 30000


l = 100\,cm

Then, we evaluate this result in the expression of the second derivative:


V'' = -600

By Second Derivative Test, we conclude that critical value leads to an absolute maximum. The maximum possible volume of the box is:


V = 30000\cdot l - l^(3)


V = 2000000\,cm^(3)

The largest possible volume of the box is 2000000 cubic meters.

User Wako
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