Question

A5.0 kg TNT explosive, initially at rest, explodes into two pieces. One of the pieces weighing 2.0 kg flies off to

the left at 36

What is the final speed of the remaining piece?

Answer 1

v = 24 m/s, rightwards

Step-by-step explanation:

Given that,

The mass of TBT explosive = 5 kg

It explodes into two pieces.

One of the pieces weighing 2.0 kg flies off to the left at 36 m/s. Let left be negative and right be positive.

The law of conservation of momentum holds here. Let v be the final speed of the remaining piece. So,

`5* 0=2* (-36)+3* v\\\\-72=-3v\\\\v=24\ m/s`

So, the final speed of the remaining piece is 24 m/s and it is in the right direction.