Question

Math class, last chance to take it!

Answer 1

`\sf x=-4`
`\sf \ and`
`\sf y=45`

Explanation:

given:

`\sf{-(1)/(2) x+(1)/(5) y=11}`

`\sf{3 x+(1)/(4) y=-(3)/(4) }`

make x subject:

`\sf{-(1)/(2) x+(1)/(5) y=11}`

`\sf{-(1)/(2) x =11-(1)/(5)y}`

`\sf{- x =22-(2)/(5)y}`

`x =-22+(2)/(5)y}`

solve using substitution method:

`\sf{3 x+(1)/(4) y=-(3)/(4) }`

`\sf{3 (-22+(2)/(5)y) +(1)/(4) y=-(3)/(4) }`

`\sf-66 +(6)/(5) y+(1)/(4) y = -(3)/(4)`

`\sf 1.45y = 65.25`

`\sf y=45`

then x will be:

`x =-22+(2)/(5)y}`

`x =-22+(2)/(5)(45)}`

`\sf x=-4`