Answer:
The expected frequency of the dominant allele, N is 0.70
Step-by-step explanation:
Total number of individuals in the insect population = 97 + 52 + 50 = 199
From Hardy-Weinberg equation, p2 + 2pq + q2 = 1; also p + q = 1
The frequency of dominant allele, N = p
Frequency of dominant NN genotype individuals = p2
From the given data: the population is comprised of 97 individuals with the NN genotype, 52 individuals with the Nn genotype and 50 individuals with the nn genotype.
Frequency of NN genotype individuals p2 = number of individuals with NN genotype Ă· total insect population
p2 = 97/ 199
p2 = 0.487
p = 0.697 = 0.70
Therefore, the expected frequency of the dominant allele, N is equal to 0.70