Answer:
50 packages of offer 1 and 50 packages of offer 2
Step-by-step explanation:
Determine How many packages of each offer do they have to sell to maximize the profit
Number of package of offer 1 = x
Number of package of offer 2 = y
Applying the LPP model
max Z = 30 x + 50 y ---- ( 1 )
now subject to the constraints from Linear programming
x + 3y ≤ 200 ------ L1
x + y ≤ 100 ------ L2
x ≥ 20 ------------- L3
y ≥ 10 -------------- L4
therefore the number of packages of each offer that can be sold to maximize profit will be : X = 50 and Y = 50 referring to equation from the LPP model considering that the shop can sell at most 100 pairs