Question

Can someone help me please

A 70.0 g piece of metal wire is heated, and the temperature of the wire changes from 58.0°C to 152.0°C. The amount of heat absorbed is 972 Joules. What is the specific heat of the metal wire?


a 0.148 J/gC

b 6.77 J/gC

c 724 J/gC

d 0.0913 J/gC

Answer 1

`c=0.1477\ J/g^(\circ) C`

Step-by-step explanation:

Given that,

Mass, m = 70 g

The temperature of the wire changes from 58.0°C to 152.0°C.

Heat absorbed, Q = 972 J

We need to find the specific heat of the metal wire. The heat absorbed is given by :

`Q=mc\Delta T\\\\c=(Q)/(m\Delta T)\\\\c=(972\ J)/(70\ g * (152-58)^(\circ) C)\\\\c=0.1477\ J/g^(\circ) C`

or

`c=0.148\ J/g^(\circ) C`

So, the correct option is (a).