Question

Pls help

1.P = 3a + 3b
Make a the subject of the formula.
2.Make a the subject of v = u + at
3.Make x the subject of 5x + 6y + 12 = 0
4.Make b the subject of A = 3b + 9
5.Make x the subject of y = 2/5x – 12

Answer 1

1)
`((P -3b))/(3) = a`

2)
`((v-u))/(a) =t`

3)
`x = (( -12-6y))/(5)`

4)
`((A-9))/(3) =b`

5)
`(5(y+12))/(2) =x`

Explanation:

1) P = 3a + 3b

First, take 3b to the left side.

P - 3b = 3a

Divide both sides by 3.

`((P -3b))/(3) = a`

2) v = u + at

First, take u to the left side.

v - u = at

Divide both sides by a.

`((v-u))/(a) =t`

3) 5x + 6y + 12 = 0

First, take 12 to the right side.

5x + 6y = -12

Take 6y to the right side.

5x = -12 - 6y

Divide both sides by 5.

`x = (( -12-6y))/(5)`

4) A = 3b + 9

First, take 9 to the left side.

A - 9 = 3b

Divide both sides by 3.

`((A-9))/(3) =b`

5) y = 2/5x – 12

First, take -12 left side.

y + 12 = 2 / 5x

Multiply both sides by 5.

5 ( y + 12 ) = 2x

Divide both sides by 2.

`(5(y+12))/(2) =x`

Answer 2

given sample: P = 3a + 3b, make a subject

• 
  `P = 3a + 3b`

• 
  `P - 3b = 3a`

• 
  `a = (P-3b)/(3)`

given sample: v = u + at, make a subject

• 
  `v = u + at`

• 
  `v - u = at`

• 
  `a = (v-u)/(t)`

given sample: 5x + 6y + 12 = 0, make x subject

• 
  `5x + 6y + 12 = 0`

• 
  `5x = - 12 - 6y`

• 
  `x = (- 12 - 6y)/(5)`

given sample: A = 3b + 9, make b subject

• 
  `A = 3b + 9`

• 
  `A -9= 3b`

• 
  `(A -9)/(3) = b`

given sample: y = 2/5x – 12, make x subject

• 
  `y = (2)/(5) x - 12`

• 
  `y +12= (2)/(5) x`

• 
  `(5(y+12))/(2) =x`

• 
  `(5y+60)/(2) =x`