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A support cable connects the top of a bridge tower to the road below.

The cable is 245.9 feet long and connects to the road at a point 200.7 feet away from the center of the bridge tower.

To the nearest tenth of a foot, how tall is the tower?

User Strah
by
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1 Answer

2 votes

Answer:

the road is 142 ft away from the center of the bridge tower.

Explanation:

Since, the bridge tower is standing vertical to the the road, therefore, the angle made by it is a right angle.

Therefore, the triangle made by cable(hypotenuse) and bridge tower (Perpendicular) on road (base) must be a right angled triangle.

Therefore, by Pythagoras theorem, we have

H² = P²+ B²

P²=H²-B²

P²=(245.9)²-(200.7)²

P=√20186.32=142.07

User Jonas Borggren
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