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22 votes
22 votes
Pls help asap !!!!!!​

Pls help asap !!!!!!​-example-1
User Runningbirds
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1 Answer

24 votes
24 votes

Answer:

The MEDIAN, 4.5 hours, is the best measure of center, so the IQR is the best measure of variability.

McKennas conclusion IS NOT accurate. The mode of her data IS 6 hours. However, MORE than half of the time, she spends LESS than 6 hours riding her horse. It would be more accurate to say that Mckenna typically rides her horse between 2.5 and 6 hours.

Explanation:

Put the values in order of smallest to largest:

0, 2, 2, 2.5, 2.5, 3, 4, 5, 6, 6, 6, 8, 9, 10

Median (middle value) = (4 + 5)/2 = 4.5

Lower quartile Q1 = 2.5

Upper quartlie Q3 = 6

IQR = Q3 - Q1 = 3.5

Mode (value that occurs most often) = 6

Mean (average) = sum of values ÷ number of values = 4.7

Range (difference between the highest and lowest values) = 10 - 0 = 10

Median is the best measure of the center since it isn't influenced by extreme values.

IQR is less affected by outliers and extreme values. It gives a consistent measure of variability for skewed data.

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The MEDIAN, 4.5 hours, is the best measure of center, so the IQR is the best measure of variability.

McKennas conclusion IS NOT accurate. The mode of her data IS 6 hours. However, MORE than half of the time, she spends LESS than 6 hours riding her horse. It would be more accurate to say that Mckenna typically rides her horse between 2.5 and 6 hours.

Pls help asap !!!!!!​-example-1
User Rsfinn
by
3.0k points