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The winning car in a race beat the second car by 19/100 of a second. The third car was 4/10 of a second behind the second car. By how much did the first car beat the third car?
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The winning car in a race beat the second car by 19/100 of a second. The third car was 4/10 of a second behind the second car. By how much did the first car beat the third car?

User Paul Androschuk
by
7.9k points

1 Answer

4 votes

Answer:

21/100 of a second

Explanation:

4/10 = 40/100

40/100 - 19/100 = 21/100

User Tim Lloyd
by
9.2k points
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