Explanation:
m<DCB + m<CBA = 180° (co-interior angles)
or, 54° + m<CBA = 180°
so, m<CBA = 180° - 54° = 126°
Now,
m<CBA + m<FAB + X = 180° (sum of interior angles of triangle)
or, 126° + 14° + X = 180°
or, X = 180° - 140°
so, X = 40°
Answer:
angleB+angleC=180° (since AB and DC are parallel and intersected by the transversal BC)
therefore, subtracting, angle B is 126°
3 angles of triangles also makes a 180°.
So, 14°+x+126°=180°
x= 180°- 140°
x=40°
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