Answer:
In ΔPQR, we have
PQ=PR⇒∠R=∠Q
Now, ST∥QR.
⇒∠PST=∠PQR and ∠PTS=∠PRQ [∵ Corresponding angles are equal]
⇒∠PST=∠Q and ∠PTS=∠R
⇒∠PST=∠PTS
⇒PT=PS
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