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Solve for ‘Theta’ if the given triangle is right triangle. Round your answer to the nearest degree.

Solve for ‘Theta’ if the given triangle is right triangle. Round your answer to the-example-1
User Laquan
by
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1 Answer

24 votes
24 votes

Answer:


sin(\theta)=(21)/(29)


\theta = 46° (nearest degree)

Explanation:

In a right triangle, the hypotenuse is the longest side and the right angle is the angle opposite the hypotenuse.

From inspection of the diagram, and measuring and comparing the side lengths, it appears the that the longest side (hypotenuse) is "base" of the triangle (the side with an unknown measure), and so the right angle is the angle formed by the vertex of sides 22 and 21.

The trig ratio for sine is:


sin(\theta)=(O)/(H)

where
\theta is the angle, O is the side opposite the angle, and H is the hypotenuse.


\implies sin(\theta)=(21)/(H)

At this stage, we don't know the measure of the hypotenuse. However, we can calculate it by using Pythagoras' Theorem
a^2+b^2=c^2 (where a and b are the legs, and c is the hypotenuse of a right triangle)


\implies 20^2+21^2=c^2


\implies c=√(20^2+21^2) =29

Therefore,


\implies sin(\theta)=(21)/(29) }


\implies \theta=46.39718103... \textdegree


\implies \theta=46 \textdegree

User Wasserholz
by
3.7k points