Answer:
126 V
Step-by-step explanation:
The computation of the rms voltage is shown below:
= I × R
=(.2) × (10)
= 2 V voltage drop across capacitor
= I × 1 ÷ (?C)
= I ÷ (2 × pi × f × C)
= (.2) ÷ (2 × pi × 10,000 × 10 × 10^-6)
= .318 V voltage drop across inductor
= I × ?L
= I × 2 × pi × f × L
= .2 × 2 × pi × 10,000 × .010
= 126 V