Question

Find the area and perimeter of a rectangle that has a length of (x + 24) and (x + 16). Show all work for full credit.

Answer 1

Perimeter of rectangle = 4x + 80

Area = x² + 40x + 384

Explanation:

Perimeter of rectangle = 2*(length + width)

= 2* (x + 24 + x + 16)

= 2*( x +x + 24 + 16) {Combine like terms}

= 2* (2x + 40)

Use Distributive property : a*(b +c) = a *b + a*c

= 2*2x + 2*40

= 4x + 80

Area of rectangle = length * width

= (x + 24) (x + 16) {use FOIL method}

= x*x + x*16 + 24*x + 24*16

= x² + 16x + 24x + 384 {Combine like terms}

= x² + 40x + 384