Question

Find the acceleration due to gravity on Titan's surface, given that its mass is 1.35 x 102kg and its radius is 2570 km

Answer 1

1.36 x
`10^(-15)`
`ms^(-2)`

Step-by-step explanation:

The equation
`g = (G*M)/(R^2)` would be used where:

g = acceleration due to gravity

G = universal gravitational constant (6.67408 ×
`10^(-11)`
`m^(3) kg^(-1) s^(-2)`)

M = mass

R = radius.

assuming the value following 10 is its exponent, which is a little confusing, the values given would simply be substituted.

Anyone can correct me if I'm wrong.