Question

How many grams of silver will be produced from 5.00 grams of copper and 1.00 gram of silver nitrate?

Cu + 2AgNO3 --> 2Ag + Cu(NO3)2
O .2299
O.635 g
O 2.38 g
O 3.86

Answer 1

mole Cu = 5 : 63.5 g/mole = 0.079

mole AgNO₃ = 1 : 170 g/mole = 0.0058

AgNO₃ as a limiting reactant

So mole Ag = mole AgNO₃ = 0.0058

mass Ag = 0.0059 x Ar Ag = 0.00588 x 108 g/mole = 0.635