Question

HELP ME PLZ ASAPPPPPP

Answer 1

`(x,y) =(-4,-3)` --- Vertex

`x = -4` --- Axis of symmetry

Explanation:

Given

`y = -6(x + 4)^2 - 3`

Solving (a): The vertex

For an equation written in

`y = a(x - h)^2 + k`

The vertex is:

`(x,y) = (h,k)`

By comparison:

`y = a(x - h)^2 + k` and
`y = -6(x + 4)^2 - 3`

`-h =4`
`k = -3`

`h =-4`
`k = -3`

So, the vertex is:

`(x,y) =(-4,-3)`

Solving (b): The axis of symmetry

For an equation written in

`y = a(x - h)^2 + k`

The axis of symmetry is:

x = h

In (a):

`h =-4`

So:

`x = -4`