16.6k views
0 votes
The side lengths of the following right triangle 15,20 and 25, as shown below. The altitude from the right angle splits the hypotenuse into line segments of length x and y. Solve for h,x, and y.

The side lengths of the following right triangle 15,20 and 25, as shown below. The-example-1
User Ezwrighter
by
4.9k points

1 Answer

5 votes

Answer:


h = 12


x = 9


y= 16

Explanation:

Given

The attached triangle

Required

Find h, x and y

Let the base of the triangle be 15.

So, the area is:


A = (1)/(2) * 15 * 20


i.e\ height = 20


A = (1)/(2) * 300


A = 150

Let the base of the triangle be 25.

So, the area is:


A = (1)/(2) * 25 * h


i.e\ height = h


A = (1)/(2) * 25h

Substitute
A = 150


(1)/(2)*25h = 150

Solve for h


h = (150 *2)/(25)


h = 6 *2


h = 12

Considering the smallest triangle


Hypotenuse = 15

So:


15^2 = h^2 + x^2


15^2 = 12^2 + x^2

This gives:


15^2 - 12^2 = x^2


81 = x^2

Take square roots


9 =x


x = 9

Solving for y


x + y = 25


y= 25 - x


y= 25 - 9


y= 16

User Vivian De Smedt
by
3.9k points