Answer:

Explanation:
Let's set up a system of equations. (1 equation for yesterday and 1 for today).
- Let h = haircut and c= color
(Yesterday: 2 haircuts and 1 color for $194).
(Today: 2 haircuts and 4 colors for $494).
Notice that both equations have a 2h. If we subtract the two equations, the 2h will cancel and leave us with one variable, c.



Since we are solving for c, we must isolate the variable. It is being multiplied by -3. The inverse of multiplication is division. Divide both sides by -3.

Now we have to solve for h. Plug 100 in for c in the first equation.

100 is being added, so we must subtract 100 from both sides.

h is being multiplied by 2, so we divide both sides by 2.

A haircut costs $47 and a color costs $100.