Question

Find an equation of the circle that has center (-2, 6) and passes through (6, 2)

Please help! I’ve tried looking for the answer and trying to solve the problem but none of the answers I’ve done are right. I need to get this question right so it’s be much appreciated if you helped me out. Thank you so much and have a great day!

Answer 1

(x+2)^2+(y-6)^2=80

Explanation:

equation of a circle :
`(x-a)^(2) +(y-b)^(2)=r^2\\`

where (a,b) is the center and r is the radius

r = distance between two points

r =
`√((6-(-2))^2+(2-6)^2) =√(8^2+(-4)^2) =√(64+16) =√(80)`

equation of the circle =
`(x+2)^2+(y-6)^2=80`