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HELP ME PLEASE!!!!! I NEED TO GET THIS RIGHT I CANT FAIL The following reaction shows the products when sulfuric acid and aluminum hydroxide react. 2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O The table shows
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HELP ME PLEASE!!!!! I NEED TO GET THIS RIGHT I CANT FAIL

The following reaction shows the products when sulfuric acid and aluminum hydroxide react.

2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

The table shows the calculated amounts of reactants and products when the reaction was conducted in a laboratory.

Initial Mass and Yield:
Sulfuric Acid Aluminum Hydroxide
Initial Amount of Reactant 40 g 1.5 g
Theoretical Yield of Water from Reactant 14.69 g 10.38 g

What is the approximate amount of the leftover reactant? (4 points)
a.11.73 g of sulfuric acid
b.10.33 g of sulfuric acid
c.11.12 g of aluminum hydroxide
d.13.67 g of aluminum hydroxide

User Johannes Matokic
by
8.1k points

1 Answer

3 votes

Answer:

c.11.43 g of aluminum hydroxide

Step-by-step explanation:

User Nicolas Gimelli
by
8.2k points
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