Question

HELP ME PLEASE!!!!! I NEED TO GET THIS RIGHT I CANT FAIL

The following reaction shows the products when sulfuric acid and aluminum hydroxide react.

2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

The table shows the calculated amounts of reactants and products when the reaction was conducted in a laboratory.

Initial Mass and Yield:
Sulfuric Acid Aluminum Hydroxide
Initial Amount of Reactant 40 g 1.5 g
Theoretical Yield of Water from Reactant 14.69 g 10.38 g

What is the approximate amount of the leftover reactant? (4 points)
a.11.73 g of sulfuric acid
b.10.33 g of sulfuric acid
c.11.12 g of aluminum hydroxide
d.13.67 g of aluminum hydroxide

Answer 1

c.11.43 g of aluminum hydroxide

Step-by-step explanation: