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Which product of prime polynomials is equivalent to 4x5 – 6x4 4x3 – 6x2? 2x2(x2 1)(2x – 3) 2x2(x2 – 1)(2x 3) x2(x2 1)(2x – 3) 2(x2 – 1)(2x 3).

2 Answers

14 votes

Answer:

The correct answer is 2x^2(x^2 + 1)(2x - 3)

Explanation:

First, you would factor out a single factor out of all of them, which is 2x^2. So, you would have 2x^2 (2x^3 - 3x^2 + 2x - 3) Then, you would use double grouping. When you have double grouped, you will have x^2(2x-3) and 1(2x-3) for the factors. The final factors for that is (x^2 + 1) and (2x - 3), then you would just put 2x^2 in the front to give you the final factorization and the correct answer stated at the top.

Explanation:

User Salw
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9 votes

Answer:

A. 2x2(x2 + 1)(2x – 3)

Explanation:

:)

User YourAboutMeIsBlank
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