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Find the area of obtuse triangle ABC when A=41 degrees, a=18cm, and b=22cm.

1 Answer

2 votes

Answer:

36 cm²

Explanation:

  • cos A= (`sqrt(b)` + `sqrt(c)` - `sqrt(a)`)/(2bc)

⇒c ≈ 5 cm

Sabc= (1/2)bcsin A ≈ 36 cm²

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