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The length of a rectangle is x feet more than its width. The area of the rectangle is 5x + 25. What is the width of the rectangle?

User Jeremy L
by
8.8k points

1 Answer

6 votes

Answer:

w =
l + (25 - l^(2))/(l - 5)

(Anyone can correct me if I'm wrong)

Explanation:

Before we start the solving, we can make the following statements:

Area = l x w

Area = 5x + 25

therefore,

l x w = 5x + 25

Since the question states that the length is x more than the width, so we can make the following statement:

w = l + x

With this, we can substitute it to the first statement we made, l x w = 5x + 25,

l x (l + x) = 5x + 25


l^(2) + lx = 5x + 25

lx - 5x = 25 -
l^(2)

x(l - 5) = 25 -
l^(2)

x =
(25 - l^(2))/(l - 5)

From this, we can find w by substituting it in the statement we made earlier, w = l + x,

w =
l + (25 - l^(2))/(l - 5)

User Lemix
by
8.2k points

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