Question

Use Charles's law to solve for the missing value:
V1 = 80.0 mL, T1 = 27°C, T2 = 77°C, V2 = ?

Answer 1

To find the missing volume (V2) using Charles's law, we need to set up an equation and solve for V2. The equation is V₁/T₁ = V₂/T₂, where V₁ and T₁ are the initial values and V₂ and T₂ are the unknowns. By substituting the given values and solving, we find that V₂ = 89.6 mL.

Step-by-step explanation:

Given: V₁ = 80.0 mL, T₁ = 27°C, T₂ = 77°C, V₂ = ?

Charles's law relates the volume of a gas to its temperature. It states that at constant pressure, the volume of a gas is directly proportional to its temperature in Kelvin. The formula for Charles's law is V₁/T₁ = V₂/T₂, where V₁ and T₁ are the initial volume and temperature, and V₂ and T₂ are the final volume and temperature.

Using the given values, we can set up the equation as follows:

80.0 mL / (273 + 27) K = V₂ / (273 + 77) K

Solving for V₂ gives:

V₂ = (80.0 mL / (273 + 27) K) * (273 + 77) K

V₂ = 89.6 mL

Answer 2

93.33 ml

Step-by-step explanation:

By Charles law we know that , volume is directly proportional to the temperature at constant pressure. So ,

→ V1/T1 = V2/T2

→ 80ml / (27+273)K = V2/(77+273)K

→ 80ml / 300K = V2/350K

→ V2 = 80ml *350/300

→ V2 = 93.33 ml

I hope this helps.