Question

2nd attempt

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Calculate AEfor a system that absorbs 599,0 kJ of heat from its surroundings
and does 3510 kJ of work on its surroundings.

Answer 1

-2911 kJ

Step-by-step explanation:

Step 1: Given data

• Heat absorbed by the system (Q): 599.0 kJ (By convention, when the systems absorbs heat, Q > 0)

• Work done by the system on the surroundings (W): -3510 kJ (By convention, when the systems does work on the surroundings, W < 0)

Step 2: Calculate the change in the internal energy (ΔE)

We will use the following expression.

ΔE = Q + W

ΔE = 599.0 kJ + (-3510 kJ) = -2911 kJ