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Please help what is the value of
tan^2(180-tetha)​

User Brc
by
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1 Answer

3 votes

Answer:

1/cos^2(180-theta) - 1

Explanation:

According to trigonometry identity

tan^2 theta + 1 = sec^2 theta

tan^2 theta = sec^2 theta - 1

hence tan^2(180-tetha)​ = sec^2 (180 -theta) - 1

tan^2(180-tetha)​ = 1/cos^2(180-theta) - 1

Hence the value of tan^2(180-tetha)​ is 1/cos^2(180-theta) - 1

User Stephen Sorensen
by
7.6k points

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