Question

If an object is projected upward with an initial velocity of 125 ft per sec, its height h after t seconds is h= - 16t+ 125t. Find the height of the object after 2 seconds.​

Answer 1

h(t) = -16t^2+125t

We need to find h(t) when t = 4 s:

h(4) = -16*4^2+125*4

h(4) = 244 ft

The height of the object after 4 seconds is 244 feet.