Question

The functions r and s are defined as follows.

r(x) =- 2x+2
s(x)=x²-2
Find the value of r(s (-2)).
r(s(-2)) = 1
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Answer 1

r(s(-2)) = -2

Explanation:

We are given these following functions:

`r(x) = -2x + 2`

`s(x) = x^2 - 2`

Find the value of r(s (-2)).

First we find the composition of r and s functions. It is:

`r(s(x)) = r(x^2-2) = -2(x^2-2) + 2 = -2x^2 + 6`

At x = -2

`r(s(-2)) = -2(-2)^2 + 6 = -8 + 6 = -2`

r(s(-2)) = -2