Question

Question 7

3 pt:
N2 + 312 --> 2N13
If 81.3 grams of lodine is reacted with 4.49 grams of nitrogen what is the theoretical yield?
(Include the correct number of significant figures but no units)
Question 8

Answer 1

84.3 g of nitrogen triiodide is the theoretical yield.

Step-by-step explanation:

Hello there!

In this case, according to the chemical reaction:

`N_2 + 3I_2 \rightarrow 2NI_3`

It is possible to compute the theoretical yield of nitrogen triiodide by each reactant via stoichiometry as shown below:

`m_(NI_3)^(by\ N_2)=4.49gN_2*(1molN_2)/(28.01gN_2) *(2molNI_3)/(1molN_2)*(394.72gNI_3)/(1molNI_3) =126.55gNI_3\\\\m_(NI_3)^(by\ I_2)=81.3gI_2*(1molI_2)/(253.81gI_2) *(2molNI_3)/(3molI_2)*(394.72gNI_3)/(1molNI_3) =84.29gNI_3`

Therefore, we infer that the smallest amount is the correct theoretical yield as it comes from the limiting reactant, in this case, diatomic iodine as it yields 84.3 g (three significant figures) of nitrogen triiodide as the theoretical yield; incidentally, nitrogen acts as the excess reactant.

Best regards!