Question

Can anyone help with this question pleasee

Answer 1

`y = 1`

Explanation:

Given:

`a^(3y - 5) = (1)/(a^2)`

Apply the negative exponent rule

`a^(3y - 5) = a^(-2)`

The bases will cancel each other

`3y - 5 = -2`

`3y - 5 + 5 = -2 + 5`

`3y = 3`

`(3y)/(3) = (3)/(3)`

`y = 1`