Answer:
The answer to your question is given below
Step-by-step explanation:
We'll begin by converting 500 cm³ to L. This can be obtained as follow:
1000 cm³ = 1 L
Therefore,
500 cm³ = 500 cm³× 1 L / 1000 cm³
500 cm³ = 0.5 L
Next, we shall determine the number of mole of Na₂CO₃ in the solution. This can be obtained as follow:
Volume = 0.5 L
Molarity = 2 M
Mole of Na₂CO₃ =?
Molarity = mole /Volume
2 = Mole of Na₂CO₃ / 0.5
Cross multiply
Mole of Na₂CO₃ = 2 × 0.5
Mole of Na₂CO₃ = 1 mole
Finally, we shall determine the mass of 1 mole of Na₂CO₃. This can be obtained as follow:
Mole of Na₂CO₃ = 1 mole
Molar mass of Na₂CO₃ = (23×2) + 12 + (16×3)
= 46 + 12 + 48
= 106 g/mol
Mass of Na₂CO₃ =?
Mass = mole × molar mass
Mass of Na₂CO₃ = 1 × 106
Mass of Na₂CO₃ = 106 g
Thus, to prepare the solution, weigh 106 g of Na₂CO₃ and dissolve in 500 cm³ (i.e 0.5 L) of water.