Answer:
5.71 N/m
Step-by-step explanation:
From the question given above, the following data were obtained:
Extention (e) = 3.5 m
Force (F) = 20 N
Spring constant (K) =?
From Hooke's law,
F = Ke
Where :
F => is the force applied
e => is the extention caused by the force
K => is the spring constant
With the above formula, we can obtain the spring constant of the spring as follow:
Extention (e) = 3.5 m
Force (F) = 20 N
Spring constant (K) =?
F = Ke
20 = K × 3.5
Divide both side by 3.5
K = 20 / 3.5
K = 5.71 N/m
Thus, the spring constant of the spring is 5.71 N/m