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10 votes
10 votes
Help Please! (100 points!)

Help Please! (100 points!)-example-1
User Jakob Christensen
by
2.2k points

2 Answers

24 votes
24 votes

(cos90°) (cos30°) – (sin90°) (sin30°)


cos (90°) = 0


sin (90°) = 1


sin (30°) =(1)/(2)


cos (30°) = ( √(3) )/(2)

Simplified :


(cos90) (cos30) – (sin90) (sin30) = - (1)/(2)

So, B)
cos (120°) = - (1)/(2)

User Hayk Mkrtchyan
by
3.1k points
11 votes
11 votes

Answer:

B is only true and the correct option.

Step-by-step explanation:


\left(cos90\right)\left(cos30\right)-\left(sin90\right)\left(sin30\right)


  • \quad \cos \left(90^(\circ \:)\right)=0

  • \quad \sin \left(90^(\circ \:)\right)=1

  • \quad \sin \left(30^(\circ \:)\right)=(1)/(2)

  • \cos \left(30^(\circ \:)\right)=(√(3))/(2)

when simplified:


\left(cos90\right)\left(cos30\right)-\left(sin90\right)\left(sin30\right) = \ -(1)/(2)

from options:

A)
cos60^\circ =(1)/(2)

✔B)
\cos \left(120^(\circ \:)\right) = -(1)/(2)

C)
sin60^\circ = (√(3) )/(2)

D)
sin120^\circ = (√(3) )/(2)

User Ryan Muller
by
2.8k points