Question

Two resistors R1 = 3 Ω and R2 = 6 Ω are connected in parallel. What is the net resistance in the circuit?​

Answer 1

"2Ω" is the net resistance in the circuit.

Step-by-step explanation:

The given resistors are:

R1 = 3Ω

R2 = 6Ω

The net resistance will be:

⇒
`(1)/(R_(net)) =(1)/(R_1) +(1)/(R_2)`

On substituting the values, we get

⇒
`(1)/(R_(net)) =(1)/(3) +(1)/(6)`

On taking L.C.M, we get

⇒
`(1)/(R_(net)) =(2+1)/(6)`

⇒
`(1)/(R_(net)) =(3)/(6)`

⇒
`(1)/(R_(net)) =(1)/(2)`

On applying cross-multiplication, we get

⇒
`R_(net)=2 \Omega`