Question

Sulfuric acid reacts with aluminum hydroxide by double replacement producing aluminum sulfate and water Write chemical reaction. If 30 g of sulfuric acid reacts with 25 g of aluminum hydroxide, identify the limiting reactant?

Answer 1

Answer:
`H_2SO_4` is the limiting reagent.

Step-by-step explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

The balanced chemical equation is:

`3H_2SO_4(aq)+2Al(OH)_3(aq)\rightarrow Al_2(SO_4)_3(aq)+6H_2O(l)`

To calculate the moles :

`\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}`

`\text{Moles of} H_2SO_4 =(30g)/(98g/mol)=0.31moles`

`\text{Moles of} Al(OH)_3=(25g)/(78g/mol)=0.32moles`

According to stoichiometry :

3 moles of
`H_2SO_4` require = 2 moles of
`Al(OH)_3`

Thus 0.31 moles of
`H_2SO_4` will require=
`(2)/(3)* 0.31=0.21moles` of
`Al(OH)_3`

Thus
`H_2SO_4` is the limiting reagent as it limits the formation of product and
`Al(OH)_3` is the excess reagent.