How much resistance is required to limit the current from a 12 V battery to 3.6 mA?

asked Feb 15, 2022 67.1k views

4 votes

by IBPX

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2 votes

Answer:

3333.3 ohm

Step-by-step explanation:

V=IR so R =V/I (in Ampere) so convert 3.6 mA to 3.6*10^-3 A

so R =12/3.6*10^-3 =3333.3

Alex Chin answered Feb 19, 2022

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