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Plz besties can you help me

a) show that k lies between - 8 and 1 in the following inequality

{k}^(2) + 7k \leqslant 8


1 Answer

2 votes

Answer:

-8≤k≤1

Explanation:

k²+7k-8≤0

(k+8)x(k-1)≤0

k1= -8

k2= 1

-8≤k≤1

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