Question

A stone is dropped from a stationary state from a high cliff and fell to the ground. After 2s the stone hit the ground. What is the velocity of the stone when it hit the surface of the ground?

Answer 1

19.6 m/s

Step-by-step explanation:

Looking at the kinematics equations, we can find one with the necessary variables; vf= v0+ at

vf is the final velocity which we are solving for, and the equation tells us the initial velocity (v0) is zero. Because the stone is dropped, it is in free fall, so we know the acceleration is acceleration due to gravity, or 9.8 m/s^2.

Plugging it all in, we can solve for vf:

vf= 0 + (9.8)(2)

vf= 19.6 m/s