Question

A plane intersects the center of a sphere

with a volume of about 9,202.8 m3. What is
the area of the cross section? Round to the
nearest tenth.

Answer 1

530.66

Explanation:

The computation of the area of the cross section is shown below

Given that

Volume = 9208 m^3

Now let us assume the radius be r

So volume = 4 ÷ 3 πr^3

9202.8 × 3 ÷ 4π = r^3

27,608.4 ÷ 4 × 3.14 = r^3

27,608.4 ÷ 12.56 = r^3

2,198.12 = r^3

r = 13

Now the area of the cross section is

= πr^2

= 3.14 × (13)^2

= 530.66